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25x^2+81=-90x
We move all terms to the left:
25x^2+81-(-90x)=0
We get rid of parentheses
25x^2+90x+81=0
a = 25; b = 90; c = +81;
Δ = b2-4ac
Δ = 902-4·25·81
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-90}{50}=-1+4/5$
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